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The Metric Structure and Sequences of Complex Numbers

If you’re going through hell, keep on going, Winston Churchill

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Introduction

Definition. Let D ⊆ ℂ be a set of complex numbers. A complex-valued function f of a complex variable defined on D is a rule that assigns to each complex number z belonging to the set D a unique complex number w, $f: D \to \mathbb{C}$.

The Metric Structure of ℂ

The complex plane ℂ carries a natural metric (distance function) inherited from its identification with ℝ².

Definition. For z₁, z₂ ∈ ℂ, the distance between them is: $d(z_1, z_2) = |z_1 - z_2| = \sqrt{(\text{Re}(z_1) - \text{Re}(z_2))^2 + (\text{Im}(z_1) - \text{Im}(z_2))^2}$

This metric satisfies the axioms:

  1. Positivity: d(z₁, z₂) ≥ 0, with equality iff z₁ = z₂
  2. Symmetry: d(z₁, z₂) = d(z₂, z₁)
  3. Triangle inequality: d(z₁, z₃) ≤ d(z₁, z₂) + d(z₂, z₃)

Sequences of complex numbers

Definition. A sequence of complex numbers is a function a $\mathbb{N} \to \mathbb{C}$, mapping natural numbers to complex numbers.

Ways to define sequences

Examples of Complex Sequences

Convergence of Sequences

Definition. A sequence $\{ a_n \}_{n=1}^∞$ is said to have a limit $L \in \mathbb{C}$ (or converges to a limit L) if $\forall \varepsilon > 0, \; \exists N \in \mathbb{N} \text{ such that } \forall n \geq N \Rightarrow |a_n - L| < \varepsilon$.

We write $\lim_{n \to \infty} a_n = L$, $a_n \to L$ or $a_n \xrightarrow{n \to \infty} L$.

A convergent sequence approaches a specific complex number L as n grows larger. an cluster around L as n grows larger.

Equivalently, for any disk B(L; ε) around L (no matter how small), all but finitely many terms of the sequence lie inside that disk. In other words, eventually all terms lie inside every disc B(L; ε)..

Formally, $\forall \varepsilon, \exist N \in \mathbb{N}$ such that $\forall n \ge N, a_n \in \mathbb{B}(a_n; \varepsilon)$. This is equivalent to the standard definition $\lim_{n \to \infty}a_n = L \iff \forall \epsilon > 0, \exist N \in ℕ \text{ such that } |a_n - L| < \epsilon, \forall n ≥ N$.

Imagine a target with center L. No matter how tiny you make the bullseye (radius ε), the “tail” of the sequence (all terms after a certain index N) will eventually land inside that bullseye and stay there forever.

Example. Consider the sequence $a_:=\frac{1}{n}+i(1−\frac{1}{n})$. As $n \to \infty, a_n \to 0+i(1−0)=i$. Thus, the limit L = i, and the sequence is convergent.

The following are all equivalent definitions of $a_n \to L$:

  1. ε-N. $\forall \epsilon > 0, \exist N \in ℕ \text{ such that } |a_n - L| < \epsilon, \forall n ≥ N$.
  2. Neighborhoods. Every neighborhood of L contains all but finitely many terms.
  3. Distance. $d(a_n, L) \to 0$ as $n \to \infty$. The distance $d(a_n, L) = |a_n - L|$.
  4. Component-wise Criterion. $a_n \to L \text{ in } \mathbb{C} \iff \begin{cases} x_n \to a \text{ in } \mathbb{R} \\ y_n \to b \text{ in } \mathbb{R} \end{cases}$.
  5. Modulus & Argument . $|a_n| \to |L|$ and (if L ≠ 0) $arg(a_n) \to arg(L)$

The Component-wise Criterion. (Reduction to Real Sequences). A complex sequence converges if and only if its real and imaginary parts converge independently.

Let $a_n = x_n + i y_n$ where xₙ, yₙ ∈ ℝ, and let L = a + ib. Then, $a_n \to L \text{ in } \mathbb{C} \iff \begin{cases} x_n \to a \text{ in } \mathbb{R} \\ y_n \to b \text{ in } \mathbb{R} \end{cases}$.

This reduces complex convergence to two real convergence problems! It allows us to prove convergence in ℂ using standard tools from real calculus (like L’Hôpital’s rule on the parts).

Proof.

(⟹) Assume $a_n \to L$. For any ε > 0, there exists N such that n ≥ N implies |aₙ - L| < ε.

Since $|x_n - a| = |\text{Re}(a_n) - \text{Re}(L)| = |\text{Re}(a_n - L)| \leq |a_n - L| < \varepsilon$, we have $x_n \to a$.

Similarly, $|y_n - b| = |\text{Im}(a_n - L)| \leq |a_n - L| < \varepsilon$, so $y_n \to b$.

(⟸) Assume xₙ → a and yₙ → b. For any ε > 0:

Let N = max(N₁, N₂). For n ≥ N: $|a_n - L| = \sqrt{(x_n - a)^2 + (y_n - b)^2} < \sqrt{\frac{\varepsilon^2}{2} + \frac{\varepsilon^2}{2}} = \varepsilon$

Therefore $a_n \to L \blacksquare$

Example: $a_n = \frac{n}{n+1} + i \sin\left(\frac{\pi}{n}\right)$.
Real part: $x_n = \frac{n}{n+1} \to 1$.
Imaginary part: $y_n = \sin(\pi/n) \to \sin(0) = 0$.
Conclusion: $a_n \to 1 + 0i = 1$.

Uniqueness of Limits. If a sequence converges, its limit is unique.

Proof.

Suppose $aₙ \to L$ and $aₙ \to M$ with L ≠ M.

Consider $\varepsilon = \frac{|L-M|}{2}$.

Since aₙ → L: ∃N₁ such that n ≥ N₁ ⟹ |aₙ - L| < ε.

Since aₙ → M: ∃N₂ such that n ≥ N₂ ⟹ |aₙ - M| < ε.

For n ≥ max(N₁, N₂): $|L - M| \leq |L - a_n| + |a_n - M| < \varepsilon + \varepsilon = |L - M|$, $|L - M| < |L - M|, this is obviously a contradiction. ∎

Examples of Convergence

  1. Spiral to the Origin. $a_n = \frac{1}{n}e^{in} = \frac{\cos n + i \sin n}{n}$
    |aₙ| = 1/n → 0. The terms spiral around the origin while approaching it.
    For any ε > 0, choose N > 1/ε. Then, for n ≥ N: $|a_n - 0| = \frac{1}{n} \leq \frac{1}{N} < \varepsilon$
  2. Convergence Along Curve. $a_n = \frac{1}{n} + i\left(1 - \frac{1}{n}\right)$
    $a_n \to 1.$
    Proof using components: $Re(aₙ) = 1/n \to 0, Im(aₙ) = 1 - 1/n \to 1$. Therefore, $aₙ \to 0 + i(1) = i.$
  3. Geometric Sequence: aₙ = zⁿ for fixed $z \in \mathbb{C}$.
    $\lim_{n \to \infty} z^n = \begin{cases} 0 & \text{if } |z| < 1 \\ 1 & \text{if } z = 1 \\ \text{diverges} & \text{if } |z| > 1 \\ \text{diverges} & \text{if } |z| = 1, z \neq 1 \end{cases}$
    Proof (case |z| < 1): Let r = |z| < 1. Then, |zⁿ| = rⁿ.
    For any ε > 0, we need rⁿ < ε, i.e., $n\cdot \log(r) \lt \log(\varepsilon) \implies[\text{Since log(r) < 0 (as 0 < r < 1)}] n > \frac{\log(\varepsilon)}{\log(r)}$.
    Choose $N = \frac{\log(\varepsilon)}{\log(r)}+1$. For n ≥ N: |zⁿ - 0| = rⁿ < ε. ∎

Divergence

Definition. A sequence $\{a_n\}_{n=1}^{\infty}$ converges to a limit $L \in \mathbb{C}$ if the terms eventually stay arbitrarily close to L. A sequence $\{a_n\}_{n=1}^{\infty}$ diverges if it does not converge to any $L \in \mathbb{C}$.

Taxonomy of Divergence

In complex analysis, “divergence” isn’t just one behavior. It helps to distinguish between two types:

  1. Divergence to Infinity (Unbounded). The sequence marches away from the origin (or grows) without bound (as n increases). Equivalently, its terms eventually leave every bounded disk.
    $a_n \to \infty$ if $\forall M > 0, \exists N$ such that $\forall n \ge N \implies |a_n| > M$.
    Examples: $a_n = n + in$. $|a_n| = \sqrt{2}n \to \infty$.
    $aₙ = n + in²$. As $n \to \infty, ∣a_n∣ = \sqrt{n²+n⁴} \to \infty$.

    In the context of the Riemann Sphere ($\hat{\mathbb{C}} = \mathbb{C} \cup \{\infty\}$), this type is considered “convergence to the point at infinity,” while the second type remains truly divergent.

  2. Bounded Divergence (Oscillation). The sequence stays within a finite region (it is bounded) but never settles on a single point (it has no limit).
    Example: $a_n = i^n = \{i, -1, -i, 1, \dots\}$
    It fits in the disk $B(0; 2)$, but has 4 different subsequential limits.

Examples of Divergence

Properties of Convergent Sequences

Theorem (Algebra of Limits). Suppose $aₙ \to L$ and $bₙ \to M$. Then:

  1. Sum: $aₙ + bₙ \to L + M$
  2. Difference: $aₙ - bₙ \to L - M$
  3. Product: $aₙ \cdot bₙ \to L \cdot M$
  4. Scalar multiple: $c \cdot aₙ \to c \cdot L$ for any c ∈ ℂ
  5. Quotient: $aₙ/bₙ \to L/M$ (provided M ≠ 0 and bₙ ≠ 0 for all n)
  6. Conjugate: $\overline{a_n} \to \overline{L}$ (continuity of conjugation).
  7. Modulus: $|aₙ| \to |L|$ (continuity of modulus).
  8. Real/Imaginary parts: $Re(aₙ) \to Re(L), Im(aₙ) \to Im(L)$

Theorem. Every convergent sequence is bounded.

An unbounded sequence cannot converge (to a finite limit).

Proof.

Suppose $a_n \to L$.

Taking ε = 1, there exists N such that n ≥ N implies |aₙ - L| < 1.

For n ≥ N: |aₙ| ≤ |aₙ - L| + |L| < 1 + |L|.

Let $M = max \{ |a_₁|, |a_₂|, \cdots, |a_{N-1}|, 1 + |L| \}.$

Then, |aₙ| ≤ M for all n. $\blacksquare$

The Squeeze/Sandwich Theorem. If |aₙ - L| ≤ bₙ for all n sufficiently large, and $b_n \to 0$, then $a_n \to L$.

Corollary. If |aₙ| ≤ cₙ where $c_n \to 0$, then $a_n \to 0.$

Examples:

For $a_n = \frac{\sin(n^2) + i\cos(n^3)}{n}$: $|a_n| \leq \frac{|\sin(n^2)| + |\cos(n^3)|}{n} \leq \frac{2}{n} \to 0$. Therefore, $aₙ \to 0$.

For $a_n = \frac{(-1)^n}{n} + i\frac{1}{n^2}, |a_n| \le \frac{1}{n}+\frac{1}{n^2} \to 0$, so $a_n \to 0$ despite oscillating real parts.

Polar Coordinates and Argument Convergence. For $a_n = r_n e^{i\theta_n} \to re^{i\theta}$:

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